Power rule of integration or the power rule of To the negative three, we're just gonna do the power rule for derivatives in reverse. Have to evaluate them at the different bounds. Of each of these parts and then we're going to And so what is this going to be equal to? Well, let's take the antiderivative So this is going to be minus one dx, so dx. Well x to the third is just over, x to the third over x to the third is just going to be equal to one. X to the negative three, and this second one, we have minus x to the I could write, I could write this as 16x to the negative three, Term right over here, let me do this in a different color. To the definite integral from negative one to negative two of, I could write this first

And now what is that going to be equal to? That is going be equal This is the same thingĪs the definite integral from negative one to negative two of 16 over x to the third minus x to the third over x to the third, minus x to the third I have xs in the numerators and xs in the denominators,īut we just have to remember, we just have to do someĪlgebraic manipulation, and this is going to seemĪ lot more attractable. Now at first this might seem daunting, I have this rational expression,

Evaluate the definite integral from negative one to negative two of 16 minus x to the third

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